Find three consecutive integers such that the sum of the first and the third is 92.

Answer 1

Here's what we know:

b - 1 = a (the first number is 2 less than the middle number)

b + 1 = c (the third number is 2 more than the middle number)

a + c = 92 (the first and third numbers total 92)

place the variable-values we know into the equation:

b - 1 + b + 1 = 92

simplify:

2b = 92

Divide by 2:

b = 46

Now just subtract 1 and add one to find the other two numbers.