Richard and Teo have a combined age of 41. Richard is 8 years older than twice​ Teo's age. How old are Richar

Answer 1

Hi Maddux,

Richard = R and Teo = T

when Richard and Teo are combined 41 it means R + T = 41

Richard is older than Teo how? Richard is 8 years older than twice​ Teo's age.

R = 8 + 2T

Now we have two equations with two variables that we need to solve a system.

There are a few methods to solve it that "substitutes" is suitable for this system

R + T = 41 #1

R = 8 + 2T #2

replace #2 in #1

8 + 2T + T = 41-----> 8 + 3T = 41-----> 3T = 41 -8 = 33------> T = 11

R = 8 + 2*11 = 30

As a result Richard is 30 and Teo is 11 years old.

you can prove it

2 times of Teo is 22 and 8 years older it means plus 8 that will be 30.

I hope it is useful,

Minoo

Answer 2

Let x be Teo's age.

Richard is 8 years older than twice Teo's age, so if Teo's age is x, then Richards age is 2x + 8.

Their combined age is 41, meaning Teo's age + Richard's age is 41.

Or x + 2x + 8 = 41.

Simplifying: 3x + 8 - 8 = 41 -8

3x = 33

3x/3 = 33/3

x = 11 (so Teo's age is 11).

To find Richard's age, substitute 11 for x in Richard's age (2x + 8):

2 * 11 + 8 = 30

So Richard's age is 30.

To verify: Teo's age (11) + Richard's age (30) = 41.