
Jacob S. answered 02/24/20
Bachelor's degree in physics, 2 years experience teaching k-12 math
If the numbers are x and y then you will have 2 equations. When x<y:
y - x = 2 y + x = 8
Solve for possible answers using each equation:
Difference Sum
y - x = 2 y + x = 8
10 - 8 = 2 7 + 1 = 8
9 - 7 = 2 6 + 2 = 8
8 - 6 = 2 5 + 3 = 8
7 - 5 = 2 4 + 4 = 8
6 - 4 = 2
5 - 3 = 2
4 - 2 = 2
Make x and y pairs:
Difference Sum
10 and 8 7 and 1
9 and 7 6 and 2
8 and 6 5 and 3
7 and 5 4 and 4
6 and 4
5 and 3
4 and 2
Finally find a pair that fits in both equations:
5 and 3 are the numbers
Summary
5 and 3 fit as the required pair because (5 - 3) = 2 and (5 + 3) =8. This pair fits the difference of 2 and sum of 8 requirements. 5 and 3 were found using the equations (y>x) y - x = 2 and y + x = 8