At t=0, h(t)=297...the initial height.
To get the height after 9 seconds , plug t=9 into the equaton of h(t).
Manisha P.
asked • 02/17/20i need help solving
NASA launches a rocket at t=0 seconds. Its height, in meters above sea-level, in terms of time is given by h=−4.9t2+199t+297.
How high is the rocket after 9 seconds?
metersHow high was the rocket when it was initially launched?
meters
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