Arturo O. answered 02/15/20
Experienced Physics Teacher for Physics Tutoring
h = initial height
If the sled went down the track without friction, its speed at the bottom is
v0 = √(2gh)
x = length of rough patch
v = final speed at the end of the rough patch
a = acceleration along the rough patch
From kinematics,
v2 - v02 = 2ax
a = f/m = -μmg/m = -μg
v2 - v02 = -2μgx ⇒
μ = (v02 - v2) / (2gx)
μ = (2gh - v2) / (2gx)
Now plug in the following values and get μ:
g = 9.8 m/s2
h = 15 m
v = 5 m/s
x = 4 m
You finish from here.