Patrick B. answered 02/14/20
Math and computer tutor/teacher
f(x+h) = (2+x+h)/(1-2x-2h)
f(x+h) - f(x) =
(2+x+h)/(1-2x-2h) - (2+x)/(1-2x)
= {(2+x+h)(1-2x) - (2+x)(1-2x-2h)} / [ (1-2x-2h)(1-2x) ]
= { 2+x+h - 4x -2x^2 - 2xh - 2 + 4x + 4h -x + 2x^2 + 2xh}/ [ (1-2x-2h)(1-2x) ]
= (5h)/[ (1-2x-2h)(1-2x) ]
Dividing by h, the difference quotient is:
5/ [ (1-2x-2h)(1-2x) ]
The limit of the difference quotient as h tends to zero is :
5/ (1-2x)^2
Quotient rule says:
[(1-2x) - (-2)(2+x)]/(1-2x)^2 =
[1 - 2x + 4 + 2x]/(1-2x)^2
5/(1-2x)^2
the domain of the original function as well as the derivative is all reals EXCEPT x=1/2