Samuel F. answered 02/14/20
Math and Science Tutor | PhD Student in Engineering
Hello Abby!
First note that
6 has factors 2 and 3
14 has factors 2 and 7
So for a number to be evenly divisible by 6 and 14 it us also be divisible by 2, 3 and 7. If a number is divisible by 3 and 7, ii must also be divisible for the product of them, 21.
Letter C