college math problem solver

Question

A waitress sold 16 ribeye steak dinners and 22 grilled salmon dinners, totaling $586.87 on particular day. Another day she sold 28 ribeye steak dinners and 11 grilled salmon dinners. Totaling $584.12. How much did each type of dinner cost

Answer 1

Let R= ribeye steak , S= salmon dinner

16R+22S=586.87

28R+11S=584.12

We want to doing elimination here:

We want to first get rid of the S variable by multiplying the bottom equation by -2

16R+22S = 586.87

-2(28R+11S=584.12)

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Now add these 2 equations together

16R+22S=586.87

-56R-22S=-1168.24

Our result:

-40R = -581.37

Solve for R (divide both sides by -40)

R= 14.53 (approximately)

Now substitute R back into one of our original 2 equations (lets choose the 1st equation)

16(14.53)+22S = 586.87

Subtract 16(14.53) from both sides:

22S = 354.39

S= 16.11 (approximately)

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Ribeye Dinner = 14.53 (approximately)

Steak Dinner = 16.11 (approximately)