Denise G. answered 02/13/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
Factor by grouping
x3 − 3x2 − 4x + 12 = 0
x2(x-3)-4(x-3)=0
(x-3)(x2-4)=0 Factor the difference of squares term
(x-3)(x-2)(x+2) Set each factor equal to zero and solve
x-3=0 Add 3 to both sides
x-3+3=0+3 Simplify
x=3
x-2=0 Add 2 to both sides
x-2+2=0+2 Simplify
x=2
x+2=0 Subtract 2 from both sides
x+2-2=0-2 Simplify
x=-2
x=3,2,-2