Irene R. answered 02/12/20
BS in Mechanical Engineering and Certified math teacher for 13 years
First let's let the variable a represent the cost of one adult ticket and the variable s represent the cost of one student ticket.
Using the information given, we can write the following equations:
2a + 3s = 12
1a + 2s = 7
Now we can solve these two equations with two unknowns using elimination by multiplying the second equation by -2 to eliminate the variable a and solve for s first:
2a + 3s = 12
-2a - 4s = -14
-1s = -2
s = 2
The cost of one student ticket will be $1.
To determine the cost of an adult ticket, substitute $1 for s in either of the original equations. Let's use the first equation:
2a + 3s = 12
2a + 3*2 = 12
2a + 6 = 12
2a +6 - 6 = 12 - 6
2a = 6
2a/2 = 6/2
a = 3
a= $3 The cost of one adult ticket will be $3 .