Raymond B. answered 02/21/20
Math, microeconomics or criminal justice
If this is an equilateral triangle, all 3 angles are equal and all 3 sides are equal.
If a side = 2x then the perimeter is 3 times 2x = 6x = 36 centimeters
6x=36
x=6
2x=12. Each side is 12 centimeters.
To find the area, put the triangle on one side, and drop a vertical line from the top to the base
That line cuts the base into two parts, each 6 centimeters.
You now have 2 right triangles, each with base 6 and height the same. The right triangles have angles 60, 30 and 90. the height is h, base is 6, and hypotenuse is 12. h^2=12^2-6^2=144-36=108
h=square root of 108. Area of each right triangle is 1/2 times 6 times square root of 108 =3sqr108
The area of both right triangles is 6sqr108 = approximately 6(10.4)=62.4 square centimeters= area of the original triangle.
Or use Heron's formula:
calculate half the perimeter: 36/2=18 subtract a side from 18: 18-12=6
multiply 18(6)(6)(6)= 18(36)6=648(6)=3888
take the square root
of 3888 = 62.4 square inches
In general for any equilateral triangle with side = s, the perimeter is 3s and the area is half side s times height of (sqr3)s
(1/4)(sqr3)s^2
or
using heron's formula sqr[(3s/2)(3s/2-s)(3s/2-s)(3s/2-s)= (3s/2-s)sqr(3s/2)(3s/2-s)
= (s/2)sqr(3s/2)(s/2)=(s/2)(s/2)sqr(3)=(s/2)^2sqr(3)
In this problem s=12, plug that into the above to get (12/2)^2 sqr(3) = 36 x 1.732 = 62.4 square centimeters
s=the perimeter divided by 3 or 36/3=12