J.R. S. answered 02/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
H2SO4 : 1.6 mol H x 1 mol H2SO4/2 mol H = 0.8 mol H2SO4
C2H4O2 : 1.6 mol H x 1 mol C2H4O2/4 mol H = 0.4 mol C2H4O2
You can now do the same process for NaOH
Ariel G.
asked 02/09/20H2SO4:
C2H4O2:
NaOH
J.R. S. answered 02/09/20
Ph.D. University Professor with 10+ years Tutoring Experience
H2SO4 : 1.6 mol H x 1 mol H2SO4/2 mol H = 0.8 mol H2SO4
C2H4O2 : 1.6 mol H x 1 mol C2H4O2/4 mol H = 0.4 mol C2H4O2
You can now do the same process for NaOH
Rebecca M. answered 02/09/20
MS in Chemistry and over 25 years industrial experience
The total number of atoms of hydrogen in the three compounds is 7. ( 2 in H2SO4, 4 in C2H4O2 and 1 in NaOH). Divide 1.6 by 7 to have 0.2286. Thus to 2 significant figures there are 0.23 of each.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.