had garden that was rectangle. it's length was twice width. decided to make a garden that was 3 feet longer and 3 feet wider than the first. find the area of the original garden let x beoriginal width

Answer 1

If the length was twice the width, we can write that as: length (L) = 2*width (W)

L=2*W

Area = length * width

A = L*W

We can substitute the first equation for L into the second:

A=(2*W)*W

A = 2*W²

If X is the original width:

A=2X²

The part about making the garden bigger is irrelevant for this part of the question.