Rebecca R. answered 02/04/20
Experienced Elementary Math, Prealgebra, Algebra 1, and Geometry Tutor
The line that passes through (-6, -6) and (4,-4) has the form y = mx + b
The slope (m) = (y2 - y1 )/(x2 - x1)
Let (x1, y1) = (-6, -6) and let (x2, y2) = (4, -4)
Then m = (-4 - (-6)) /(4-(-6)) = 2/10 = 1/5
So, now you have:
y = 1/5(x) + b where b is the y intercept.
So, substituting one of the points into the equation (we'll use (4, -4)):
-4 = 1/5(4) + b
b = -4 - 4/5
b = -4 4/5 or -24/5 (This is the y-intercept that you needed to find)
So, now we can get our final equation of the line passing through these 2 points:
y = (1/5)x - (24/5)
Now , you find the x-intercept by substituting 0 for y in the above equation:
0 = 1/5x - 24/5
(1/5)x = 24/5
x = (24/5)/(1/5) = 24
Therefore, the answer to your problem is:
The x-intercept is the point (24, 0 )
The y-intercept is the point (0,-24/5)