Hi Jehanna B.,
Let L = the length of the rectangle.
Let W = the width of the rectangle.
Let P = the perimeter
The perimeter of the rectangle is equal to twice the length plus twice the width, P = 2L + 2W.
And the rectangles length (L) is (=) six less than twice its width (2W - 6), L = 2W - 6.
We are also given the perimeter, P = 54. We can set P equal to 54 and substitute L = 2W -6 into P = 2L + 2W, and solve for W, then solve for L.
P = 2L + 2W
54 = 2(2W - 6) + 2W, (substitute P = 54 and L = 2W - 6)
54 = 4W - 12 + 2W, (multiplied through)
66 = 6W, (added 12 to both sides and add 4W + 2W)
11 = W, (divide both sides by 6)
Now we need to find the length (L) by substituting W = 11 into our perimeter equation:
P = 2L + 2W
54 = 2L + 2(11), (substitute P = 54 and W = 11)
54 = 2L + 22, (multiplied)
32 = 2L, (subtract 22 from both sides)
16 = L, (divided both sides by 2)
I hope this helps, Joe.