Joseph D. answered 02/04/20
Algebra 2 Tutor with the help you need.
Hi Lucy S.,
For (fg)(x), this is the same as f(x)*g(x), and with f(x) = x2 - 9 and g(x) = x + 1, we can find (fg)(x).
(fg)(x)=
f(x) * g(x)=
(x2-9)*(x+1)=
(x2)(x)+(x2)(1)+(-9)(x)+(-9)(1)=
x3 + x2 -9x - 9
I hope this helps, Joe.