Hi Lucy S.,
For (fg)(x), this is the same as f(x)*g(x), and with f(x) = x2 - 9 and g(x) = x + 1, we can find (fg)(x).
(fg)(x)=
f(x) * g(x)=
(x2-9)*(x+1)=
(x2)(x)+(x2)(1)+(-9)(x)+(-9)(1)=
x3 + x2 -9x - 9
I hope this helps, Joe.
Lucy S.
asked 02/04/20In the space provided, type the answer in descending order as it applies without any spaces between the letters, numbers, or symbols.
Hi Lucy S.,
For (fg)(x), this is the same as f(x)*g(x), and with f(x) = x2 - 9 and g(x) = x + 1, we can find (fg)(x).
(fg)(x)=
f(x) * g(x)=
(x2-9)*(x+1)=
(x2)(x)+(x2)(1)+(-9)(x)+(-9)(1)=
x3 + x2 -9x - 9
I hope this helps, Joe.
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