Need help on math question!

Question

How far did the basketball fall?

Solve for H

Using this formula:

h=1/2gt^2+v0t+h0

g= -9.8 or -32

our times:

time 1: 1.6 seconds

time 2: .98 seconds

time 3: 1.5 seconds

the average: 1.36 seconds

how do we find out the initial height and the initial velocity?

Answer 1

The initial height is h(t) evaluated at h = 0, which is h₀. The initial velocity is the v₀ in the second term of h(t). The height at any time t is just h(t) evaluated at the particular value of t of interest. The distance it fell by time t is the difference between h(t) and the initial height h₀.