Consider g(x)=-(x+6)^2-2. Identify the vertex

Question

Can someone plz help me

Answer 1

A more general form would be y = a(x-h)^2 +k. The vertex is (h,k) = (-6,-2) as per Kat.

However, I don't see why we should assume -2 is a misprint and should have been 2. And had it been 2, then

k = 2 and the vertex would be (-6,2), not (-6,0)

Answer 2

You first look at the function and the generic function y=(x-h)^2 +k

The vertex is the hand k in the function that you are given.In the function given

1. I assume that the -2 is misprint and that it should have been 2
2. the h is -6 and the k is 0 because there is nothing behind the ( ).
3. IF the function should have been written as y= (x+6)^2 -2 then the h= -6 and the k = -2
4. So this makes the vertex (-6. -2) if it was written as the example in # 3 or (-6.0) it is was written as in # 1.