Steven K. answered 01/26/20
In-Depth, Motivational Math Tutor, B.S. Pure Math, Computer Science
The bathtub is 72L. At 3L/s, it would take 24s to fill. At 4L/s, it would take 18s to fill. But it only took 20s. So, what we do is we write and equation in terms of time, t. Suppose t seconds passed before the rate changed and 20-t seconds afterward. Notice that t + (20-t) = 20. The bathtub filled with 3(t) liters beforehand and 4(20-t) liters afterward. Thus, in total, there is 3(t) + 4(20-t) liters in the tub. Since we know there is 72L in the tub, we have that 3(t) + 4(20-t) = 72. Now, we solve for t.
Here we go.
We have 3(t) + 4(20-t) = 72.
Then, 3t + 4(20) - 4t = 72.
Then, 3t + 80 - 4t = 72.
Then, -t + 80 = 72.
Then, -t = -8.
Then, t = 8.
Eight Seconds! The rate changed after eight seconds!
So, how much water was in tub beforehand? Oh, right, it was 3(t) = 3(8) = 24L.
Twenty-four Liters! That's like a bunch, I think.
Anna S.
Thank you soo much! I just could not think how to make this into an equation that I could solve.01/26/20