need help please solve!

Question

The area of a rectangle is 128 sq. ft. If the width is twice the length, what is the measure of the length of the rectangle?

Answer 1

To find the area,

-width * height = 128 square feet

The width is twice as long as the the length

-Width = Length * 2. We can express this as:

W = 2L

And then multiply the length and the width.

L * 2L = 128

When we multiply 2L * L, we get '2L squared, which can be written as 2L^2:

2L^2 = 128

Divide each side by 2.

2L^2 / 2 = 128 / 2

Now, we have:

L^2 = 64

We want the Length, L, by itself. So, we will take the square root (√) of each side.

√L^2 = √64

The square root of L^2 is L. The square root of 64 is 8.

L = 8

Therefore, the length of the rectangle is 8 feet.

Answer 2

Here's what we know:

A = Lw (Area of a rectangle is length times width)

w = 2L (width is twice the length)

A = 128 (area is 128 ft²)

Place the values into the equation:

128 = 2L²

Divide by 2:

64 = L²

Find the square root of the above for the final answer.