Peter K. answered 01/22/20
Math / Statistics / Data Analytics
Kala can take from 0 to 5 classes out of courses labeled A, B, C, D , E, G; 6 classes.
She can choose 0 of the classes 1 way.
She can choose 1 of the classes 6 ways.
She can choose 2 of the classes 15 ways (6 ways to choose the first and 5 ways to choose the 2nd divided by two for double counting, A,B and B, A are the same).
She can choose 3 of the classes 20 ways (6 ways to choose the first and 5 ways to choose the 2nd, 4 ways to choose the 4th; the pattern is 6!/[(6-number chosen)!*number chosen!] in this case 6!/[(6-3)!*3!].
She can choose 4 classes 15 ways
She can choose 5 classes 6 ways.
That means she can create 1 + 6 + 15+ 20 +15 + 6 = 63 different class selections of from 0 to 5 classes out of 6.
Terri S.
Well, I got the answer wrong. My teacher said the answer is 63.01/22/20
Peter K.
1 + 6 + 15+ 20 +15 + 6 = 63, right.01/22/20
Peter K.
I had written: 1 + 6 + 15+ 20 +15 + 6 = 6201/22/20
Peter K.
The order doesn't matter. We use nCr = n!/[(n-r)!r!]01/22/20
Peter K.
for n = 0 to 501/22/20
Peter K.
sorry r = 0 to 5 and n = 601/22/20
Terri S.
Is this the answer even if the order of classes doesn't matter?01/22/20