Find three consecutive integers such that the sum of the largest and 5 times the smallest is -244.

Answer 1

Let the smallest integer be: x. Since our three integers need to be consecutive, they would be:

x, x + 1, and x + 2

The largest plus 5 times the smallest would be:

(x + 2) + 5(x) = - 244

x + 2 + 5x = - 244

6x + 2 = - 244

6x = - 246

x = - 41

The smallest integer is - 41.

That means the three integers are:

smallest: - 41

middle number: -41 + 1 = - 40

largest number: - 41 + 2 = - 39

Answer 2

Let the integers be represented by x, x+1, x+2

so largest is x+2 and 5 times the smallest is 5x.

x + 2 + 5x= -244

6x + 2 = -244

6x = -246

x = -41

Therefore the 3 consecutive integers are: -41, -40, -39