Two times the sum of three consecutive odd integers is 30. Find the largest integer algebarically

Answer 1

Whenever you have 3 (or an odd number of) consecutive odd or even integers being summed, the middle number will be the average, and can therefore be set = n, and the sum in this case will be 3n. (Formally, the integers could be labeled n - 2, n, and n + 2).

Twice the sum is 6n = 30, so n = 5 and the largest will be 5 + 2 = 7.

Answer 2

Choose integers 2n-1, 2n+1 and 2n+3

2 times the sum is 12n + 6 = 30

Yo can solve for n...n=2 and the integers are...you get 'em!