
Mark M. answered 01/15/20
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
x = -2
y = -3
h = √13 By Pythagoras
sin θ = y / h, -3 / √13
csc θ = h / y, √13 / -3
tan θ = y / x, -3 / -2
cot θ = x / y, -2 / -3
Huzaifa J.
asked 01/14/20Let , −3−2
be a point on the terminal side of θ
.Find the exact values of sinθ
, cscθ
, and cotθ
Mark M. answered 01/15/20
Mathematics Teacher - NCLB Highly Qualified
Draw and label a diagram!
x = -2
y = -3
h = √13 By Pythagoras
sin θ = y / h, -3 / √13
csc θ = h / y, √13 / -3
tan θ = y / x, -3 / -2
cot θ = x / y, -2 / -3
Hi Huzaifa J.,
With (-3, -2) on the terminal side:
tan(θ) = y/x = -2/-3 = 2/3
Therefore:
θ = tan-1(2/3) = 33.69o or 0.588 radians.
With this value for θ, you can use your calculator to find the remaining values for:
sin(θ),
csc(θ) = 1/sin(θ),
cot(θ) = 1/tan(θ).
I hope this helps, Joe.
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