If a line goes through (3,5) and (-7,3), what is the y value when x=11?

Answer 1

Find the slope of the line m=(y₂-y₁)/(x₂-x₁)

Slope=(3-5)/(-7-3) = -2/-10 = 1/5

Find the y-intercept using one of the points and the slope:

5=(1/5)3+b

5=(3/5)+b

4.4=b

So the equation of the line is y=(1/5)x + 4.4

To find what y is when x is equal to 11, plug it into that equation:

y = (1/5)(11) + 4.4

y = 2.2 + 4.4

y = 6.6

So when x=11, y=6.6

Answer 2

Slope of this line m = (5 - 3)/(3 - (-7)) = 2/10 = 1/5.

Then using point-slope equation of a line we have: y - 5 = 1/5(x - 3), y = 1/5x + 5 - 3/5; y = 1/5x + 22/5.

If x = 11 then y = 11/5 + 22/5 = 33/5 = 6.6

Answer 3

First, find the slope:

m = (y₂ - y₁) / (x₂ - x₁)

You know x₁, y₁, x₂, and y₂. Plug in the numbers and get m.

Next, write the point slope form of the equation.

y - y₁ = m(x - x₁)

You can also use

y - y₂ - m(x - x₂)

Plug in the value of m from above, plug in x=11, and solve for y.