If it's going through (1,-1), and parallel to y=-6x, what is the slope-intercept.

Answer 1

When two lines are parallel, they have the same slope. The slope of the line y = -6x is "-6", so the line we are looking for has a slope of -6 and goes through the point (1, -1). You can find the equation a couple of ways.

Using the Point-Slope equation:

The Point-Slope equation is y - y₁ = m(x - x₁) where "m" is the slope and the point it goes through is (x₁, y₁) so the equation of the line is:

y - (-1) = -6(x - 1)

y + 1 = -6x + 6

y = -6x + 5

Using the Slope-Intercept form:

The Slope-Intercept equation is y = mx + b where "m" is the slope and "b" is the y-intercept. so the equation in this case is y = -6x + b but we still need "b". To find it, we can plug in the point (1, -1) as an (x, y) where x = 1 and y = -1. So:

y = -6x + b

-1 = -6(1) + b

-1 = -6 + b

5 = b

Now we can plug in the value of "b" to get:

y = -6x + 5

Answer 2

We can use the point-slope equation (Y - y1) =m(X-x1)

The point is (1,-1) and the slope is -6. Parallel lines all have the same slope.

(Y- (-1)) = -6(X-1)

Y+1=-6x+6

Y=-6x+5

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