Math Algebra Homework

Question

a party rental company has chairs and tables for rent. the total cost to rent 2 chairs and 3 tables is 23. the total cost to rent 6 chairs and 5 tables is 43. what is the cost to rent each chair and each table.

Answer 1

You can solve this problem using a system of equations. Let's let c represent the cost of one chair and t represent the cost of one table.

Using the info in your problem, we can write the following two equations:

2c + 3t = 23

6c + 5t = 43

We can multiply the first equation by -3 to solve the system:

-6c + -9t = -69

6c + 5t = 43

-4t = -26

t = $6.50

Now we can use the second equation (or the first if you prefer) to find the cost of 1 chair because we now know that the cost of a table is $6.50:

6c + 5t = 43

6c + 5* 6.50 = 43

6c + 32.50 = 43

6c + 32.50 - 32.50 = 43 - 32.50

6c = 10.50

c = $1.75

So the cost to rent one table is $6.50 and the cost for one chair is $1.75