Maria J.

asked • 01/08/20

I have a z values statistics question.

A population is normally distributed with µ=36 and δ=10 What is the probability of randomly selecting a value that is greater than 45?


I get 18,41%, but on my lecture slides the answer is : Area between mean and z (0.9) = 0.3159 Area beyond z (0.9) = 0.1841 P(X>43) = area>45 = 0.5000+0.1841 = 0.6841 = 68.41% Therefore, the probability of randomly selecting a value that is greater than 45 is 68.41%


So, I am really confused, thanks for any help!

1 Expert Answer

By:

John B. answered • 01/08/20

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