Twice the difference of a number and 6 is equal to three times the sum of the number and 9

Answer 1

Let's let x represent the missing number. Then the "twice the difference of a number and 6" would be written as: 2(x-6)

Next, "three times the sum of the number and 9" would be represented as: 3(x + 9)

Lastly, "is equal to " would be represented as: =

Combining these expressions gives the equation:

2(x - 6) = 3(x + 9)

Use inverse operations and the distributive property to solve:

2(x - 6) = 3(x + 9)

2x - 12 = 3x + 27

2x -12 - 2x = 3x + 27 - 2x

-12 = x + 27

-12 - 27 = x + 27 - 27

-39 = x