A parallelogram has an area of 6x^2-7x-5 and has a base of 3x - 5. What is the ratio of the area to the base?

Answer 1

First factor 6x^2 - 7x - 5 to (3x - 5) ( 2x + 1).

Then the raio of area to the base can represented by: (3x - 5) ( 2x + 1)/ (3x - 5)

The (3x-5) terms will cancel out (create a one) and the ratio of area to the base becomes (2x + 1 ) to 1

Answer 2

6x²- 7x-5:(3x-5)=(2x+1)(3x-5)/(3x-5)=2x+1

3x-5 cannot be equal 0 is a condition to cancel 3x-5 from both denominator and numerator