What is equation in standard form of the line that has x-intercept of 6 and y-intercept of -2

Answer 1

There is more than one way to work this. Here is one way:

y = mx + b

You have the points (6,0) and (0,-2), Get the slope m.

m = (-2 - 0) / (0 - 6) = 1/3

b = -2

y = (1/3)x - 2

Multiply both sides by 3 to get standard form.

3y = x - 6

x - 3y = 6