
John M. answered 12/28/19
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
Cal J.
asked 12/28/19John M. answered 12/28/19
Math Teacher/Tutor/Engineer - Your Home, Library, MainStreet or Online
David W. answered 12/28/19
Experienced Prof
Here are the very easy equations that fit this problem:
Quadratic equation: y = x2
System with two solutions:
y = x2
y = 1 (red line)
y = x2
1 = 12 and 1 = (-1)2
The two solutions: (1,1) and (-1,1)
System with one solution:
y = x2
y = 0 (blue line)
0 = (0)2
The one solution is (0,0)
No solution to system:
y = x2
y = x - 1
There is no square of a number that is one less than the original number.
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