Let A = the team wins the first game and B = the team wins the second game
P(B I A) = P(A and B) / P(A) = 0.38 / 0.70 = 0.54
Jaheim L.
asked • 12/25/19Please help me this is hard.
The volleyball team has a double-header on Friday. The probability that they will win both games is 38%. The probability that they will win just the first game is 70%, What is the probability that the team will win the second game given that they have already won the first game?
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