Find the equation of the line perpendicular to y=-2/3x-7 that runs through the point (6,1) in slope intercept form

Answer 1

y = mx + b

The product of slopes of perpendicular lines is -1, so

m = -1/(-2/3) = 3/2

y = (3/2)x + b

Use the given point to find b.

1 = (3/2)(6) + b

1 = 9 + b

b = -8

y = (3/2)x - 8