12 vans and 6 buses carry 408 students while another 6 vans and 2 buses carry 136 students if buses and vans carry the same amount of students how many students are in each bus and each van?

Answer 1

168 students in each bus

zero students in each van

12V+6B=408 V= number of students in each van, B = number in each bus

6V+2B=136, multiply that by 2 and subtract from first equation.

12V+6B=48 minus 12V+4B=272, that gives 2B=136 or B=68

If B=68, then V=0

but the question is ambiguous, as by carrying same numbers of students, you may mean they carry the same for each of the buses and the same for each of the vans, or possibly you meant the van carries the same as the bus.

IF the latter, then it's possibly different.

Let x = the number of students the van or bus carries and they're the same.

Then it's 12x+6x=408 or 18x=408 and x=408/18=22 and 2/3 of a student, an unlikely possibility.

and 6x+2x=136 or 8x=136 and x=136/8=17. x can't be 17 and 22 2/3 at the same time,

so the latter possibility of the ambiguous question has no solution