What is the equation of a line parallel to y=3x+1 that passes through the point at (-2, -4)

Answer 1

The standard form: y = mx + b

Your given line has a slope of 3, and a parallel line will have the same slope.

Plug in the slope and the values for the given point, and solve for b

Answer 2

Your given line has a slope of 3, and a parallel line will have the same slope.

Now use the slope-point form

y - y_a = m (x - x_a) where point is A(x_a, y_a) (-2, -4)

So you will get

y - (-4) = 3 (x - (-2) )

or

y+4 = 3(x+2)