A concession stand sells candy and soda during athletic events

Question

A concession stand sells candy and soda during athletic events. At one particular football game they sold 710 items and were able to raise 1310 dollars. If candy costs one dollar and sodas cost two dollars each, determine how many sodas and how many pieces of candy they sold at the game

Answer 1

First, set up a system of equations. The first will be for items sold, and the second one is for the price/sales. Let c be candy and s be soda.

c + s = 710

1c + 2s = 1310

Solving the first equation for c, we get c = 710 - s Plugging it into the second equation:

710 - s + 2s = 1310

710 + s = 1310 (simplifying)

s = 600 sodas

We can now find the number of candy sold by using the first equation.

c + 600 = 710

c = 110 candy pieces

Answer 2

cx+sy=1310

c+s=710

c1+s2=1310

There's different combinations. Need more imfo.