Michael has a jar of dimes and nickels. There are 152 dimes and nickels in the jar that total $11

Answer 1

Let n = number of nickels

Let d = number of dimes

n + d = 152

5n + 10d = 1100

(5n + 10d = 1100)/5

n + 2d = 220

- n + d = 152

d = 68

n + 68 = 152

- 68 - 68

n = 84

Michael has 84 nickels and 68 dimes in a jar.

Answer 2

10x+5y=11

x+y=152

68 dimes

84 nickles

Answer 3

Let d=dimes, n=nickels

Write two equations:

total coins: d+n=152

total value 0.10d+0.05n=11

use substitution to solve. From the first equation we obtain d=152-n.

plug that in and we get 10(152-n)+0.05n=11

solve and we obtain our answers. n=84 nickels and d=68 dimes.

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