The sum of three consecutive integers is 5 more than the sum of the first and second. What is the third number?

Answer 1

Let N = 3rd integer

Let N - 1 = 2nd integer

Let N - 2 = 1st integer

Then the sum of three consecutive integers is (N-2) + (N-1) +N=3N-3

The sum of the first and 2nd integers = (N-2) +(N-1) = 2N-3

Then we got the equation should be

(3N-3) - (2N-3) = 5

3N-3-2N+3=5

N=5

Thus the third number is 5.

Answer 2

Let N = 3rd integer

Let N - 1 = 2nd integer

Let N - 2 = 1st integer

Then the Sum of these integers is = 3N - 3

The sum of the first and 2nd integers = 2N - 2

We need to solve this equation for N:

3N - 3 = 5 + (2N - 2)

= 2N + 3

N = 6, ans