How di I find the Slope-Intercept form of perpendicular to the line y=-2x-7; passes through (-3,10)

Answer 1

The line perpendicular to this one will have a slope equal to the negative reciprocal. In the equation provided, the slope is -2. So m=1/2 for the line perpendicular. Then you can use the following equation. (y-y1)=m(x-x1)

Plug in the values of (x1,y1) using the point provided. (-3,10)

(y-10)=1/2(x-(-3)) Simplify

(y-10)=1/2(x+3)Distribute

y-10=1/2x+3/2 Add 10 to both sides

y-10+10=1/2x+3/2+10 Simplify

y=1/2x+23/2

Answer 2

Since the lines are perpendicular, we can find the slope of the second line by taking the opposite reciprocal of the first, meaning since our original slope is -1/2, our new slope is 2/1 or 2, so m = 2.

Now, we take the point (-3, 10) and the slope of m = 2, and plug all the values in to y = mx + b to solve for b:

y = mx + b

10 = 2(- 3) + b

10 = -6 + b

16 = b

So, the equation your are looking for is: y = 2x + 16