Mark H. answered • 12/06/19
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correct!!
Jesset C.
asked • 12/06/19ALGEBRA PROBLEM!
2i7 - i4 + 2√-3 √-12 + 3√-4
(A) -19 - 2i
(B) -13 + 4i
(C) 11 + 4i
(D) -11 - 8i
(E) none of the above
For this I got (B) -13 + 4i, is this the correct answer?
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2 Answers By Expert Tutors
Aaron M. answered • 12/06/19
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Is there supposed to be a sign before the radical of -12? That would clarify things a bit.
Aaron M.
Ok, that seems reasonable. 2i7 - i4 + 2√-3 √-12 + 3√-4 breaks down into -2(i^7) or -2(1)(-i) or 2i. Subtract i^4 which is 1, then add (2i√3)(2i√3) which is -12. Next comes 6i. Add all together, 6i+(-2i√3)^2-5 and you'd get (6-2√3i)-1 or 1+8i. The only reasonable answer here is (E).
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12/06/19
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Mark H.
I assumed that it was simply 2(√-3)(√-12)12/06/19