Algebra Question!

Question

The volume of a quantity of an ideal gas was held constant. The initial temperature of 600 kelvins was reduced to 144 kelvins. If the initial pressure was 250 newtons per square meter, what was the pressure after the temperature change?

(A) 1041(2/3) newtons/m²

(B) 345.6 newtons/m²

(C) 60 newtons/m²

(D) 41(2/3) newtons/m²

(E) None of the above

For this I got (C) 60 newtons/m², is this correct?

Answer 1

At constant volume,

P₁/T₁ = P₂/T₂ ⇒

P₂ = (T₂/T₁) P₁ = (144/600)(250) N/m² = 60 N/m²

Note: The given temperatures were in K. If they were given in °C, you would have to first convert to K before taking the ratio of temperatures.