A rectangle has a length that is 4 more than twice the width. If the perimeter is 128 yards, find the rectangle’s dimensions.

Answer 1

Let x=width

length = 2x+4 (This is 4 more than twice the width)

Perimeter = all 4 sides added together

128 = x + x + (2x+4)+ (2x+4) Simplify by combining like terms

128 = 6x+8 Subtract 8 from both sides

128-8 = 6x+8-8 Simplify

120 = 6x Divide both sides by 6

120/6 = 6x/6 Simplify

x=20 cm is the width

Solve for length

length = 2x+4 = 2(20)+4 = 44 cm is the length