math line and points y intercept

Question

There

is

a

line

whose

y	-intercept

is

^-10

and

whose

slope

is

0

.

What

is

its

equation

in

slope

-intercept

form?

Answer 1

Alright, it looks like the question is asking us for the equation of a line that has a y-intercept at -10 and a slope of zero. In slope intercept form, the equation looks like y = mx + b. M is the slope, and if it's zero then that means we have y = 0(x) + b. Anything times zero is zero, so all that gives us y = 0 + b. B is equal to the y-intercept of the line, and they gave that to us, it's -10. So we can substitute -10 in for b and we finally get y = 0 + (-10) or, y = -10. That's your equation: y = -10. Hope that helps!

For more info about what the line looks like and how we get there, here's some help!

The y-intercept means that the line will cross the y-axis at -10, so we know that it will touch there. The slope is how steep the line is (like how steep a ski slope is) and if it's zero, that means it's totally flat. So the line will not go up or down, it will just be a horizontal line. If it crosses the y-axis at -10, then it will be a horizontal line going left and right from y=-10.

Answer 2

The slope-intercept form of a linear equation is

y = mx + b

where m is the slope and b is the y-intercept.

For this problem we are told that the y-intercept is -10 and the slope is 0. Substituting 0 for m and -10 for b we get

y = 0x + (-10)

We can simplify this to

y = -10.

Any line with a slope of zero is a horizontal line. x can be any value, but y will always be -10.