Alright, it looks like the question is asking us for the equation of a line that has a y-intercept at -10 and a slope of zero. In slope intercept form, the equation looks like y = mx + b. M is the slope, and if it's zero then that means we have y = 0(x) + b. Anything times zero is zero, so all that gives us y = 0 + b. B is equal to the y-intercept of the line, and they gave that to us, it's -10. So we can substitute -10 in for b and we finally get y = 0 + (-10) or, y = -10. That's your equation: y = -10. Hope that helps!
For more info about what the line looks like and how we get there, here's some help!
The y-intercept means that the line will cross the y-axis at -10, so we know that it will touch there. The slope is how steep the line is (like how steep a ski slope is) and if it's zero, that means it's totally flat. So the line will not go up or down, it will just be a horizontal line. If it crosses the y-axis at -10, then it will be a horizontal line going left and right from y=-10.