How is sin-1(-1/2)=-pi/6 ?? Be more specific with answer please

Answer 1

If θ = sin^-1x, then sinθ = x where -π/2 < θ < π/2.

So, sin^-1(-1/2) is the angle θ between -π/2 and π/2 such that sinθ = -1/2. So, θ = -π/6.