Char Array Programming. Need to write a c++ programming that can count alphabets in a sentence but not include other characters and space .Alphabets only

Question

Char Array:

Write a program that will read in char array of size N. Allow the user to fill in the array.

As each component is read, print it only if it is not a duplicate of a character already read. Count the number of occurrence for each character.

Example: input

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Output:

Character used:

t h i s w e b u c o k a l n y r f  

number of occurrence

t= 5

h=3

i=5

s=7

w=2

e=5

b=1

u=1

.

.

f=2

Hint:

·       Can use more than 1 array to solve this problem.

·       Only alphabet count only (space and other characters not counts)

Answer 1

using namespace std;

#include <iostream>

#include <ctype.h>

#include <stdlib.h>

#include <string.h>

#define MAX_STR_BUFF_LENGTH (99999)

void GO ( char * strBuff, int * freq)

{

int n = strlen(strBuff);

for (int iLoop=0; iLoop<n; iLoop++)

{

char chChar = strBuff[iLoop];

chChar = toupper(chChar);

if ((chChar>='A') && (chChar<='Z'))

{

freq[chChar-65]++;

}

}

}

int main()

{

int freq[26];

char strBuff[MAX_STR_BUFF_LENGTH];

memset(freq,0,26*sizeof(int));

cout << "Input the string :>";

gets(strBuff);

GO(strBuff,freq);

cout << "CHAR FREQ" << endl;

for (int iLoop=0; iLoop<26; iLoop++)

{

char chChar = char(iLoop+65);

cout << chChar << " " << freq[iLoop] << endl;

}

}