Perpendicular lines,,, help pls?

Question

Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the following equation

Point: (-6,5)

Equation: x-y=5

Answer 1

The line x - y = 5 has slope 1.

So, any line perpendicular to x - y = 5 has slope -1.

The line with slope -1 and which passes through the point (-6,5) has equation:

y - 5 = -1(x - (-6))

y - 5 = -x - 6

y = -x -1

Answer 2

Its slope must be the negative reciprocal of the slope of the given line, so

m = -1 / [-1/(-1)] = -1

y = mx + b

y = -x + b

5 = -(-6) + b

b = -1

y = -x - 1

Test the answer.