Looking at the money taken in, the expressions would look like
Initial Case M = 550*97
One Reduction M = (550 + 30)(97 - 1)
Two Reductions M = (550 + 30 + 30)(97 - 1 - 1)
So,
Let E = the number of extra shoes sold, then express the Money (M) expression as
M = (550 + 30E)(97 - E) = 53,350 + 2360E -30E2
Now, taking the derivative dM/dE and setting this equal to zero, we have
2360 -60E = 0 or E = 39.33
This means that a reduction of $39.33 will give the maximum profit. But since the reduction is in $1 increments, you would do $39 or $40 & you will find that a $39 reduction is the maximum (You can check this!)
Therefore, The shoe price of $97 - $39 = $58 results in the maximum profit!