Math problem please help

Question

What is the x and y intercepta of the following equations

2y = x- 1

And

X = 1/3y + 1

And

Y = 3x

And

Y = 1/3x + 12

Answer 1

Hi again, Logan.

This is what you MUST MEMORIZE:

To find x-intercept: FORCE Y=0

To find y-intercept: FORCE X=0

With 2y = x - 1 x-int: 2(0) = x - 1 0 = x - 1 1 = x so the x-intercept is 1

y-int: 2y = 0 - 1 2y = -1 y = -(1/2) so the y-intercept is -(1/2)

With x = (1/3)y + 1 x-int: x = (1/3)(0) + 1 x = 0 + 1 x = 1 so the x-intercept is 1

y-int: 0 = (1/3)y + 1 -1 = (1/3) y -3 = y so the y-intercept is -3

With y = 3x x-int: 0 = 3x x=0 x-intercept is 0

y-int: y = 3(0) y = 0 y-intercept is 0

With y = (1/3)x + 12 x-int: 0 = (1/3)x + 12 -12 = (1/3)x -36 = x x-intercept is -36

y-int: y = (1/3)(0) + 12 y = 0 + 12 y = 12 y-intercept is 12

Answer 2

Hi Logan S.,

Please convert each equation to the standard slope-intercept form:

y = mx + b

where m and b are the slope and the intercept respectively.

You should know how to add and subtract terms from each side to keep the equality, or divide or multiply each side (as a whole) to also keep the equality. That's all it takes!

Cheers, -- Mr. d.