The word has 9 letters with 2 letters occurring twice each.
Number of arrangements = 9! / [(2!)(2!)] = 9! / 4 = (9)(8)(7)(6)(5)(3)(2)(1) = 90,720
Juwan M.
asked 11/14/19The word has 9 letters with 2 letters occurring twice each.
Number of arrangements = 9! / [(2!)(2!)] = 9! / 4 = (9)(8)(7)(6)(5)(3)(2)(1) = 90,720
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